Question

I want to concatenate two const char* but when I do this I got these symbols: `�b

I do the following:

 char* path = new char[strlen(args->targetFileName) + strlen(args->targetFilePath)];
cout << path << endl;
strcat(path,args->targetFilePath);
cout << path << endl;
strcat(path,args->targetFileName);
cout << path << endl;

Output:

`�b
`�b/home/user/Arbeitsfläche/
`�b/home/user/Arbeitsfläche/Auto.png

Whats the fault?? Any suggestions??

Answer 1

The array is containing uninitialized memory. Your strcat is searching for the first 0 byte, and there is no guarantee where it is, or if there even is any (in which case strcat would even search after the allocated memory, probably incarnating the invoked UB as a crash).

Set the first byte to 0 when using strcat, or better yet, use C++ and use std::string.