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Home/ Questions/Q 7836765
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T14:18:11+00:00 2026-06-02T14:18:11+00:00

I want to convert a char array[] like: char myarray[4] = {‘-‘,’1′,’2′,’3’}; //where the

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I want to convert a char array[] like:

char myarray[4] = {'-','1','2','3'}; //where the - means it is negative

So it should be the integer: -1234
using standard libaries in C. I could not find any elegant way to do that.

I can append the ‘\0’ for sure.

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  1. Editorial Team
    Editorial Team
    2026-06-02T14:18:13+00:00Added an answer on June 2, 2026 at 2:18 pm

    I personally don’t like atoi function. I would suggest sscanf:

    char myarray[5] = {'-', '1', '2', '3', '\0'};
    int i;
    sscanf(myarray, "%d", &i);
    

    It’s very standard, it’s in the stdio.h library 🙂

    And in my opinion, it allows you much more freedom than atoi, arbitrary formatting of your number-string, and probably also allows for non-number characters at the end.

    EDIT
    I just found this wonderful question here on the site that explains and compares 3 different ways to do it – atoi, sscanf and strtol. Also, there is a nice more-detailed insight into sscanf (actually, the whole family of *scanf functions).

    EDIT2
    Looks like it’s not just me personally disliking the atoi function. Here’s a link to an answer explaining that the atoi function is deprecated and should not be used in newer code.

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