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Home/ Questions/Q 8835857
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T09:21:26+00:00 2026-06-14T09:21:26+00:00

I want to convert a String, lets say abc , to an int with

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I want to convert a String, lets say "abc", to an int with the corresponding ascii: in this example, 979899.

I’ve run into two problems:

1) what I wrote only works for characters whose ascii is two characters long and

2) since these numbers get very big, I can’t use longs and I’m having trouble utilizing BigIntegers.

This is what I have so far:

BigInteger mInt = BigInteger.valueOf(0L);
for (int i = 0; i<mString.length(); i++) {
        mInt = mInt.add(BigInteger.valueOf(
                (long)(mString.charAt(i)*Math.pow(100,(mString.length()-1-i)))));
}

Any suggestions would be great, thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-14T09:21:28+00:00Added an answer on June 14, 2026 at 9:21 am

    What’s wrong with doing all the concatenation first with a StringBuilder and then creating a BigInteger out of the result? This seems to be much simpler than what you’re currently doing.

    String str = "abc";  // or anything else
    
    StringBuilder sb = new StringBuilder();
    for (char c : str.toCharArray())
        sb.append((int)c);
    
    BigInteger mInt = new BigInteger(sb.toString());
    System.out.println(mInt);
    
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