Question

I want to convert an ip address read from a file in the decimal format (192.168.65.72) to one in binary format {110000001010100001000001010001000}.I am reading the ip address in the decimal format from a file.Find the code snippet below.

/*contains 192.168.65.72*/
filter = open("filter.txt", "r")

for line in filter:
    bytePattern = "([01]?\d\d?|2[0-4]\d|25[0-5])"
    regObj = re.compile("\.".join([bytePattern]*4))
    for match in regObj.finditer(line):
        m1,m2,m3,m4 = match.groups()
        print "%s %s %s %s" %(m1, m2, m3, m4)

I want to convert m1,m2,m3 and m4 each into an 8bit binary value.I cannot figure out a way to do that.I am new to python.Any help will be greatly appreciated.

Cheers.

Answer 1

''.join([ bin(int(x))[2:].rjust(8,'0') for x in '123.123.123.123'.split('.')])