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Home/ Questions/Q 597197
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:15:15+00:00 2026-05-13T16:15:15+00:00

I want to convert the following code: … urls = [many urls] links =

  • 0

I want to convert the following code:

...
urls = [many urls]
links = []
funcs = []
for url in urls:
   func = getFunc(url, links)
   funcs.append(func)
...

def getFunc(url, links):
   def func():
      page = open(url)
      link = searchForLink(page)
      links.append(link)
   return func

into the much more convenient code:

urls = [many urls]
links = []
funcs = []
for url in urls:
   <STATEMENT>(funcs):
        page = open(url)
        link = searchForLink(page)
        links.append(link)

I was hoping to do this with the with statement. As I commented bellow, I was hoping to achieve:

def __enter__():
    def func():

..code in the for loop..

def __exit__():
  funcs.append(func)

Of course this doesn’t work.

List comprehensions is not good for cases were the action searchForLink is not just one function but many functions. It would turn into an extremely unreadable code. For example even this would be problematic with list comprehensions:

for url in urls:
  page = open(url)
  link1 = searchForLink(page)
  link2 = searchForLink(page)
  actionOnLink(link1)
  actionOnLink(link2)
  .... many more of these actions...
  links.append(link1)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:15:16+00:00Added an answer on May 13, 2026 at 4:15 pm

    A bit unconventional, but you can have a decorator register the func and bind any loop variables as default arguments:

    urls = [many urls]
    links = []
    funcs = []
    
    for url in urls:
        @funcs.append
        def func(url=url):
            page = open(url)
            link = searchForLink(page)
            links.append(link)
    
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