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Home/ Questions/Q 9122841
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T06:11:53+00:00 2026-06-17T06:11:53+00:00

I wan’t to copy a specific folder structure containing files and folders and have

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I wan’t to copy a specific folder structure containing files and folders and have an output that tells the user how far the copying is.

Currently I use the following to copy the structure whithout some specific folders:

cp -rfv !(Project.buildoutput) $Project_SYNC_DIR

But the cp -v output is very ugly:

> _55_studio.tests/singles/CustomIdentifier.file -> /Users/<path>/_55_studio.tests/singles/CustomIdentifier.file build.sh
> -> /Users/<path>/build.sh

Is it possible to output only the Level 1 elements with a clean name.

My current folder structure:

_55_studio
--singles
--mixed
_55_studio.tests
--singles
build.sh
project.settings

output to following while copying:

Copy folder _55_studio
Copy folder _55_studio.tests
Copy file build.sh
Copy file project.settings

Is there an efficient way to achieve this and how?

BR,
mybecks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T06:11:54+00:00Added an answer on June 17, 2026 at 6:11 am

    Here in a one-liner using find:

    find "/path/to/dir" -maxdepth 1 -mindepth 1 -name "Project.buildoutput" -prune -o -exec /bin/bash -c "echo -en \"Copy \"; \
                                                                                                          [ -d '{}' ] && echo -en \"folder \";\
                                                                                                          [ -f '{}' ] && echo -en \"file \"; \
                                                                                                          basename '{}'; \
                                                                                                          cp -fr '{}' \"$Project_SYNC_DIR\"" \;
    

    Output:

    Copy folder _55_studio
    Copy folder _55_studio.tests
    Copy file build.sh
    Copy file project.settings
    
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