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Home/ Questions/Q 9193351
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T21:08:28+00:00 2026-06-17T21:08:28+00:00

I want to count the spaces in a string: public class SongApp { public

  • 0

I want to count the spaces in a string:

public class SongApp {
    public static void main(String[] args) {
        String word = "a b c";

        int i =0,spaceCount=0;

        while(i<word.length()){

            char temp = word.charAt(i);         
            System.out.println(temp);
            if(" ".equals(temp)){
                spaceCount++;
            }
            i++;            
        }
        System.out.println("Spaces in string: "+spaceCount);
    }
}

When I replace the if statement with if(temp.equals(" ")), I get a “cannot invoke(String) on the primitive type char.

I don’t understand why this won’t work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T21:08:30+00:00Added an answer on June 17, 2026 at 9:08 pm

    It won’t work because you are calling a method of Class String (equals()) on a value which is of primitive type ‘char’. You are trying to compare a ‘char’ with a ‘String’.

    You must compare between ‘char’s and since it’s a primitive value you need to use ‘==’ boolean compare operator like:

    public class SongApp {
    
        public static void main(String[] args) {
    
          String word = "a b c";
          int i = 0,
          spaceCount = 0;
    
          while( i < word.length() ){
            if( word.charAt(i) == ' ' ) {
                spaceCount++;
            }
            i++;
          }
    
          System.out.println("Spaces in string: "+spaceCount);
        }
    }
    
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