Question

I want to create a class lets say Employee that implements the generic interface Comparable and overrides the methods equals, hashCode, and toString…How would I be able to do it ?

would this be ok

interface MinMax<T extends Comparable<T>> {

T equals();
T hashCode();
T toString();

}

and

class Employee<T extends Comparable<T>> implements MinMax<T> {

 public T equals(){

  }

  public T hashCode(){

  }

  public T toString(){

  }



  }

Answer 1

There are two parts to the question.

Part 1: Override equals, hashCode and toString.

Simply redefine those methods in you new class with your new implementation.

class Employee {

    //fields and other methods

    public boolean equals(Object other) {
        //new implementation here
    }
    public int hashCode() {
        //make sure two equal objects produce the same hashCode
    }
    public String toString() {
        //return whatever you want here
    }
}

Part 2: Implement the Comparable interface.

I assume you wish to compare to other employees. Declare that it implements Comparable, and implement the compareTo method described by the interface.

public Employee implements Comparable<Employee> {

    //fields and methods

    public int compareTo(Employee e) {
        //new implementation. Should probably be consistent with equals.
    }
}