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Home/ Questions/Q 9283403
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T18:37:24+00:00 2026-06-18T18:37:24+00:00

I want to create a function that will create dynamic levels of nesting in

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I want to create a function that will create dynamic levels of nesting in a python dictionary.
e.g. if I call my function nesting, I want the outputs like the following:

nesting(1)  :  dict = {key1:<value>}
nesting(2)  :  dict = {key1:{key2:<value>}}
nesting(3)  :  dict = {key1:{key2:{key3:<value>}}}

and so on. I have all the keys and values before calling this function, but not before I start executing the code.

I have the keys stored in a variable ‘m’ where m is obtained from:

m=re.match(pattern,string)

the pattern is constructed dynamically for this case.

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  1. Editorial Team
    Editorial Team
    2026-06-18T18:37:26+00:00Added an answer on June 18, 2026 at 6:37 pm

    You can iterate over the keys like this:

    def nesting(level):
        ret = 'value'
        for l in range(level, 0, -1):
            ret = {'key%d' % l: ret}
        return ret
    

    Replace the range(...) fragment with the code which yields the keys in the desired order. So, if we assume that the keys are the captured groups, you should change the function as follows:

    def nesting(match): # `match' is a match object like your `m' variable
        ret = 'value'
        for key in match.groups():
            ret = {key: ret}
        return ret
    

    Or use reversed(match.groups()) if you want to get the keys in the opposite order.

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