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Home/ Questions/Q 7529143
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T04:34:50+00:00 2026-05-30T04:34:50+00:00

I want to create a mongoID using an URI fragment as source. However, unless

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I want to create a mongoID using an URI fragment as source. However, unless the URI really contains a properly formatted mongoId, I get the below error thrown.

What should I change to allow _id creation without throwing errors as wrapping it in a try/catch block doesn’t do it?

Error:

500 Error: Argument passed in must be a single String of 12 bytes or a
string of 24 hex characters in hex format

The code:

var _id = db.bson_serializer.ObjectID.createFromHexString(req.params.id);

this.db.users.findById(_id, function(err, doc) {
    if (!err && !!doc) { res.send(JSON.stringify(doc)); } else {res.send(JSON.stringify({error: "Not found"));}
});

I use the mongoskin driver.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T04:34:51+00:00Added an answer on May 30, 2026 at 4:34 am

    The error is being thrown on this line:

    var _id = db.bson_serializer.ObjectID.createFromHexString(req.params.id);
    

    If you wrap that in try/catch block it should work.

    var _id = null
    try {
      _id = db.bson_serializer.ObjectID.createFromHexString(req.params.id);
    } catch (err) {
      res.send(JSON.stringify({error: "Not found"}));
      return;
    }
    
    this.db.users.findById(_id, function(err, doc) {
      if (!err) { 
        res.send(JSON.stringify(doc)); 
      } else {
        res.send(JSON.stringify({error: err.message}));
      }
    });
    

    Does this work for you?

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