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Home/ Questions/Q 6643873
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:06:03+00:00 2026-05-26T00:06:03+00:00

I want to create a pointer to an array of pointers (with 10 pointers

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I want to create a pointer to an array of pointers (with 10 pointers in the array), then I want to give a pointer a value.

This is what I have so far:

char **arraypointer = calloc (10, sizeof (char*));

How will I give value to this array?

I’ve tried:

arraypointer[0] = "string"

But I get a seg fault.

Edit:

I want to create a pointer that points to an array of pointers. Each of these pointers will have a struct property. How is it possible to access the struct property for this pointer? I have no code to post because I am still trying to figure out how it should look. The struct for this pointer will contain a string which is a char *string and an int number. I am thinking of it working like this:

arraypointer[0]->string = "this";
arraypointer[0]->number = 3;
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  1. Editorial Team
    Editorial Team
    2026-05-26T00:06:03+00:00Added an answer on May 26, 2026 at 12:06 am

    Update:

    struct mystruct* pointer = calloc(N, sizeof(struct mystruct));
    pointer[0].string = "this"; //notice . instead of ->
              ^
    pointer[0].number = 3;
              ^
    

    Original answer:

    char **arraypointer = calloc (10, sizeof (char*));
    arraypointer[0] = "string";
    

    These two lines are perfectly fine. You’d get a segfault(Undefined behavior, actually) if you tried to do something like

    arraypointer[0][3] = 's';
    

    later.

    Also, you’d get in trouble if you did

    strcpy(arraypointer[0], "string");
    

    because you haven’t actually allocated any memory that arraypointer[i] point to

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