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Home/ Questions/Q 883039
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T12:31:17+00:00 2026-05-15T12:31:17+00:00

I want to create a Rails 3 route with entirely optional parameters. The example

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I want to create a Rails 3 route with entirely optional parameters. The example broken route is:

match '(/name/:name)(/height/:height)(/weight/:weight)' => 'people#index'

Which results in ‘rake:routes’ yielding:

/(/name/:name)(/height/:height)(/weight/:weight)

And thus adding an initial slash to all links:

<a href="//name/kevin">...</a>

The route works if I specify it as:

match '/people(/name/:name)(/height/:height)(/weight/:weight)' => 'people#index'

But I want to have this as the root URL (as with the first example, which does not work). Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-15T12:31:18+00:00Added an answer on May 15, 2026 at 12:31 pm

    I don’t know if this can be done with Rails’ routing engine, but you can add a custom middleware to your stack and it should work just fine.

    Put this in lib/custom_router.rb

    class CustomRouter
      def initialize(app)
        @app = app
      end
    
      def call(env)
        if env['REQUEST_PATH'].match(/^\/(name|height|weight)/)
          %w(REQUEST_PATH PATH_INFO REQUEST_URI).each{|var| env[var] = "/people#{env[var]}" }
        end
        @app.call(env)
      end
    end
    

    and add

     config.middleware.use "CustomRouter"
    

    to your config/application.rb.

    You can then set the route like

    match '/people(/name/:name)(/height/:height)(/weight/:weight)' => 'people#index'
    

    and it will work.

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