I want to create a transpose function for dynamic 2d arrays. I want the functions to have as parameters the 2d array and the rows and columns. I ve decided to use double pointer. However i m a bit confused about how i gonna call the function from main. So i ve got the above code
#include<iostream>
using namespace std;
void transposeMatrix(double **mat, int rows, int columns)
{
mat = new double*[rows];
for (int i = 0; i < rows; ++i)
{
mat[i] = new double[columns];
}
double temp;
for (int i = 0; i<rows; i++)
{
for (int j = i+1; j<columns; j++)
{
temp=mat[i][j];
mat[i][j]=mat[j][i];
mat[j][i]=temp;
}
}
cout<< "\n";
for (int i = 0; i<rows; i++)
{
for (int j = 0; j<columns; j++)
{
cout << mat[i][j] << " \t";
}
cout << "\n";
}
}
int main()
{
int rows = 10;
int columns = 10;
double mat[rows][columns];
for (int i = 0; i<rows; i++)
{
for (int j = 0; j<columns; j++)
{
mat[i][j] = j;
}
}
for (int i = 0; i<rows; i++)
{
for (int j = 0; j<columns; j++)
{
cout << mat[i][j] << " \t";
}
cout << "\n";
}
//mat = new double[50][1];
transposeMatrix(mat, 10, 10);
system("pause");
return 0;
}
Any idea?
You’re very close. You’re calling the function correctly and the function’s parameter list is correct. First, remove this section from the transpose function:
Now make sure all your brackets match up. (There was one missing.)
You can’t define a static array (one that looks like this:
x[y][z]) with non-constant variables as the size arguments. (I.e.yandzmust be constants.) But actually, you’re passing a dynamic array to the transpose function anyway, androwsandcolumnsdon’t have to be constants to do that. So, in main, define a dynamic array like this:After that, your code should work. But you could also make it better by putting your matrix display code in a function. Then, instead of cutting and pasting it everywhere, all you have to do is call the function! It’s an important habit to get into. Have fun!