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Home/ Questions/Q 4331930
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T10:11:01+00:00 2026-05-21T10:11:01+00:00

I want to create an authorization filter for my web app(To be able to

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I want to create an authorization filter for my web app(To be able to restrict access to certain pages).

I created a simple .xml file with the pages that each user is allowed to visit:

  <access>
    <buyer>
        <page>buyoffer.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </buyer>
    <seller>
        <page>sellerpanel.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </seller>
    <administrator>
        <page>sellerpanel.xhtml</page>
        <page>faq.xhtml</page>
        <page>index.jsp</page>
        <page>login.xhtml</page>
        <page>main.xhtml</page>
        <page>registrationSucceded.xhtml</page>     
    </administrator>
</access>

Then i need to do parsing to extract the value of the pages, to be able to create conditions to allow or redirect(Depending). I just need somebody to tell be how to extract the values of those pages from the xml. This is what i did till now:

public class RestrictPageFilter implements Filter {

    private FilterConfig fc;
    private DocumentBuilder builder;
    private Document document;

    public void init(FilterConfig filterConfig) throws ServletException {
        // The easiest way to initialize the filter
        fc = filterConfig;
        // Get the file that contains the allowed pages
        File f = new File("/allowedpages.xml");
        // Prepare the file parsing
        try {
            builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
            document = builder.parse(f);
        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

    public void doFilter(ServletRequest request, ServletResponse response,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest req = (HttpServletRequest) request;
        HttpServletResponse resp = (HttpServletResponse) response;
        HttpSession session = req.getSession(true);
        String pageRequested = req.getRequestURL().toString();

        // Get the value of the current logged user
        Role currentUser = (Role) session.getAttribute("userRole");
        if (currentUser != null) {
            if(currentUser.getType().equals("BUYER")) {
                //Loop BUYER Element of the .xml
                //if pageRequested.contains(value of the page at buyer element)             
                // chain.doFilter(request, response);
                // Else
                // Redirect the user to the main page
            }
            else if(currentUser.getType().equals("SELLER")) {
                //Same as above just for seller element
            }
            else if(currentUser.getType().equals("ADMINISTRATOR")) {
                //Same as above just for administrator element
            }           
        }
    }

    public void destroy() {
        // Not needed
    }
}

In the comments inside the doFilter method is explained what i need to do. Could someone give me a tip on how i should iterate through the file to find the page names for each of the user types? I try to follow JAXP examples from the internet, but they are more complex than what i need.

Update
The xml is stored in WEB-INF/classes

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T10:11:02+00:00Added an answer on May 21, 2026 at 10:11 am

    Rather use JAXB. JAXP is an old and very verbose API. JAXB leans on Javabeans and is therefore clean and relatively easy. First create a Javabean which maps 1:1 to the XML file using javax.xml.bind annotations.

    @XmlRootElement
    public class Access {
    
        @XmlElement
        private User buyer;
    
        @XmlElement
        private User seller;
    
        @XmlElement
        private User administrator;
    
        public User getBuyer() {
            return buyer;
        }
    
        public User getSeller() {
            return seller;
        }
    
        public User getAdministrator() {
            return administrator;
        }
    
        public static class User {
    
            @XmlElement(name="page")
            private List<String> pages;
    
            public List<String> getPages() {
                return pages;
            }
    
        }
    
    }
    

    Then execute the following piece to map it (assuming that allowedpages.xml is placed in root of the classpath).

    InputStream input = Thread.currentThread().getContextClassLoader().getResourceAsStream("allowedpages.xml");
    Access access = (Access) JAXBContext.newInstance(Access.class).createUnmarshaller().unmarshal(input);
    

    Note that you should NOT use new File() for this. See also getResourceAsStream() vs FileInputStream.

    Finally you can access all buyer pages as follows:

    List<String> buyerPages = access.getBuyer().getPages();
    // ...
    

    Needless to say that homegrowing security isn’t always the best practice. Java EE 6 ships with container managed security.

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