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Home/ Questions/Q 8593509
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Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T00:00:25+00:00 2026-06-12T00:00:25+00:00

I want to create json object from a string that comes as a response

  • 0

I want to create json object from a string that comes as a response from a servlet in my server.

public class JSONParser {

static InputStream is = null;
static JSONObject jObj = null;
static String json = "";

// constructor
public JSONParser() {

}

    public JSONObject getJSONFromUrl(String url,String a) {

        ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
        postParameters.add(new BasicNameValuePair("branchname", a));

        try {
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            httppost.setEntity(new UrlEncodedFormEntity(postParameters));

            HttpResponse httpResponse = httpClient.execute(httppost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();          

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

        // try parse the string to a JSON object
        try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }


        return jObj;            
}}

This is my servlet..

public class AvailabilityResponse extends HttpServlet {

@Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {

    PrintWriter out=response.getWriter();

        String br_id;
        br_id=request.getParameter("branchname");

    try{
                Class.forName("com.mysql.jdbc.Driver").newInstance();
                Connection con=DriverManager.getConnection("jdbc:mysql://localhost:8888  /atmlivedetails","root","root");  
        Statement st=con.createStatement();
        ResultSet rs=st.executeQuery("select atmbrno, atmbrname  from location_stat where act_brname='"+br_id+"'");
        int i=0;
        JSONArray jArray = new JSONArray();
        while(rs.next()){

    String s = rs.getString("atmbrno");
    String t = rs.getString("atmbrname");

    JSONObject arrayObj = new JSONObject();

    arrayObj.put("atmbrno",s);
    arrayObj.put("atmbrname",t);

    jArray.add(i,arrayObj);
    i++;
    }
    rs.close ();
    st.close ();
    out.print(jArray);
}

    catch(Exception e){
            out.print(e);
    }


}}

but when I run this it says Error

"parsing data org.json.JSONException: Value [{"atmbrname":"ANURADAPURA
[ATM 2]","atmbrno":"ATM084"},{"atmbrname":"MANNAR BRANCH  
","atmbrno":"ATM344"}] of type org.json.JSONArray cannot be converted
to JSONObject"

what is the wrong in this case?

Here is my calling class

public class ListAtmActivity extends ListActivity{

private static String url ="http://10.0.2.2:8080/hello/AvailabilityResponse";

//TextView error;
//String brName;

//Bundle b = getIntent().getExtras();
//String brName = b.getString("key");

private static final String TAG_CONTACTS = "contacts";
private static final String TAG_ID = "id";
private static final String ATM_NO = "atmbrno";
private static final String ATM_PLACE = "atmbrname";

// contacts JSONArray
//JSONArray contacts = null;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.list_item);

    String brName=getIntent().getExtras().getString("key");


    /*Bundle b = getIntent().getExtras();
    brName = b.getString("key");
    */


    // Hashmap for ListView
    ArrayList<HashMap<String, String>> contactList = new ArrayList<HashMap<String, String>>();

    // Creating JSON Parser instance
    JSONParser jParser = new JSONParser();

    // getting JSON string from URL
    JSONObject json = jParser.getJSONFromUrl(url,brName);


    try{
        //String results;
        JSONArray contacts = json.getJSONArray(TAG_CONTACTS);

        for(int i = 0; i < contacts.length(); i++){
            JSONObject json_data = contacts.getJSONObject(i);

            // Storing each json item in variable
            String atm_id = json_data.getString(ATM_NO);
            String atm_name = json_data.getString(ATM_PLACE);

            HashMap<String, String> map = new HashMap<String, String>();

            map.put(ATM_NO, atm_id);
            map.put(ATM_PLACE, atm_name);

            contactList.add(map);                
        }                       
    }

    catch(JSONException e) {
        e.printStackTrace();

    }

    /**
     * Updating parsed JSON data into ListView
     * */
   ListAdapter adapter = new SimpleAdapter(this, contactList,
            R.layout.list_main,
            new String[] { ATM_NO, ATM_PLACE }, new int[] {
                    R.id.name , R.id.email });

    setListAdapter(adapter);

}}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T00:00:26+00:00Added an answer on June 12, 2026 at 12:00 am

    you can change json object to json array,

      public class JSONParser {
    
    static InputStream is = null;
    static JSONArray jObj = null;
    static String json = "";
    
    // constructor
    public JSONParser() {
    
    }
    
        public JSONArray getJSONFromUrl(String url,String a) {
    
            ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();
            postParameters.add(new BasicNameValuePair("branchname", a));
    
            try {
                // defaultHttpClient
                DefaultHttpClient httpClient = new DefaultHttpClient();
                HttpPost httppost = new HttpPost(url);
                httppost.setEntity(new UrlEncodedFormEntity(postParameters));
    
                HttpResponse httpResponse = httpClient.execute(httppost);
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();          
    
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
    
            try {
                BufferedReader reader = new BufferedReader(new InputStreamReader(
                        is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                is.close();
                json = sb.toString();
            } catch (Exception e) {
                Log.e("Buffer Error", "Error converting result " + e.toString());
            }
    
            // try parse the string to a JSON Array
            try {
                jObj = new JSONArray(json);
            } catch (JSONException e) {
                Log.e("JSON Parser", "Error parsing data " + e.toString());
            }
    
    
            return jObj;            
    }}
    

    Your return data is json array, but you convert json object ,that’s only Exception raise.

      static JSONArray jObj = null;
    
       // try parse the string to a JSON Array
        try {
            jObj = new JSONArray(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }
    
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