Question

I want to create my wsdl by spring-ws automatically and I inserted the code below to my app context file, but I got the error;

“Cannot locate BeanDefinitionParser for element [dynamic-wsdl]”

what does that mean and what can I do? tnx

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:sws="http://www.springframework.org/schema/web-services"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org   /schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/web-services http://www.springframework.org/schema/web-services/web-services-2.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">


<bean id="payloadMapping"
       class="org.springframework.ws.server.endpoint.mapping.PayloadRootQNameEndpointMapping">
    <property name="defaultEndpoint" ref="inferenceEndPoint" />
    <property name="interceptors">
        <list>
            <ref local="validatingInterceptor" />
            <ref local="payLoadInterceptor" />
        </list>
    </property>
</bean>

<bean id="payLoadInterceptor"
    class="org.springframework.ws.server.endpoint.interceptor.PayloadLoggingInterceptor" />

<bean id="validatingInterceptor"
    class="org.springframework.ws.soap.server.endpoint.interceptor.PayloadValidatingInterceptor">
    <description>
        This interceptor validates the incoming
        message contents
        according to the 'Request.xsd' XML
        Schema file.
    </description>
    <property name="schema" value="/WEB-INF/schemas/Request.xsd" />
    <property name="validateRequest" value="true" />
    <property name="validateResponse" value="false" />
</bean>

<bean id="inferenceEndPoint" class="com.mywebsite.ws.web.InferenceEndPoint">
    <property name="messageService" ref="messageService" />
</bean>

<bean id="messageService" class="com.mywebsite.ws.service.MessageService">
    <property name="inferenceService" ref="inferenceService" />
</bean>

<bean id="schema" class="org.springframework.xml.xsd.SimpleXsdSchema">
    <property name="xsd" value="/WEB-INF/schemas/Request.xsd" />
</bean>

  <sws:dynamic-wsdl id="mtwsdl"
    portTypeName="mtWS"
    locationUri="http://localhost:8080/mws/">
<sws:xsd location="/WEB-INF/schemas/Request.xsd" />
   </sws:dynamic-wsdl>
<bean id="inferenceService" class="com.mywebsite.ws.im.InferenceService">
    <property name="webServiceConfiguration" ref="playerConfiguration" />
</bean>

<!-- <bean id="inferenceConfig" class="com.mywebsite.ws.im.InferenceService"> 
    <constructor-arg ref="playerConfiguration"/> </bean> -->

<!-- ~~~~~~~ Application beans ~~~~~~~ -->
<bean id="playerConfiguration"
    class="com.mywebsite.ws.configuration.WebServiceConfiguration"
    init-method="init">
    <property name="playerConfigXml" value="/WEB-INF/config/webserviceconfiguration.xml" />
    <property name="executingPathResource" value="/WEB-INF" />
    <property name="developmentMode" value="true" />
</bean>

Answer 1

I suggest you look at the class path and also server run time path, I think you may have both (spring-ws 1.5.x and spring-ws 2.x) version’s of jar files either in the compile/run time path. If that is not the case clean up the both class and run time path and add only spring-ws 2.x jar files.

As for the differences, when spring framework name space handler (WebServicesNamespaceHandler) encounters (dynamic-wsdl tag in spring context file), It will register a (DynamicWsdlBeanDefinitionParser) bean with all the properties specified in the dynamic wsdl tag. It is essentially same as you registering (DefaultWsdl11Definition) bean in spring context.