Question

I want to create tags using echo function but I’m stuck here; I dont know how to make it through.

This is what I want to do:

echo "<img src=$row['one'] style="width:100px"/>" ;

(Note: $row['one'] is a variable of php script and that contains the path of the image), but it throws me these error:

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\xampp\htdocs\im.php on line 13

I want these statement to execute in php and I tried this way too:

echo '<img src=$row['one'] styel="width:100px" />';

These time I get the error:

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\im.php on line 13

I know where the error is. The error is most probably here

'<img src=$row[' //here's the error, right?

I worked on c and quite some other languages. I know that in c, to use double quotes in the printf we follow up some syntax but I dont know what to do in php.

Answer 1

You need to escape the ":

echo "<img src=\"{$row['one']}\" style=\"width:100px\" />";

or you use single quotes and do this:

echo '<img src="', $row['one'], '" style="width:100px" />';

There is never a need to concatenate in order to echo. You can always just use ,. The php manual explains the differences between ' and " in the chapter on strings.

As a goodie, because you mentioned printf, this works in php, too:

printf('<img src="%s" style="width:100px"/>', $row['one']);