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Asked: 2026-05-13T15:36:42+00:00

I want to declare my own numeric types, exactly like unsigned int, but I

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I want to declare my own numeric types, exactly like unsigned int, but I do not want the types to be implicitly converted. I tried this first:
typedef unsigned int firstID;
typedef unsigned int secondID;

but this is no good as the two types are just synonyms for unsigned int, so are freely interchangable.

I’d like this to cause an error:

firstID fid = 0;
secondID sid = fid; // no implicit conversion error

but this to be okay:

firstID fid = 0;
secondID sid = static_cast<secondID>(fid); // no error

My reason is so that function arguments are strongly typed, eg:

void f( firstID, secondID ); // instead of void f(unsigned int, unsigned int)

What is the mechanism I am looking for?

Thanks

Si

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1 Answer

  1. Editorial Team

    Maybe BOOST_STRONG_TYPEDEF form boost/strong_typedef.hpp would help.

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