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Home/ Questions/Q 6250133
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:21:55+00:00 2026-05-24T13:21:55+00:00

I want to define a method to make sums between different type numbers: <T>

  • 0

I want to define a method to make sums between
different type numbers:

<T> void add (T one, T two)
{
    T res = one + two; 
}

the above method not work because type erasure convert T into Object
and thus the + operator is not defined on Object…

How can do that?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:21:56+00:00Added an answer on May 24, 2026 at 1:21 pm

    You’ll have to use a bounded type parameter:

    public <T extends Number> double add (T one, T two)
    {
        return one.doubleValue() + two.doubleValue(); 
    }
    

    Note that it uses double as return type because that’s the primitive numeric type that covers the largest range of values – and one or both parameters could be double too. Note that Number also has BigDecimal and BigInteger as subclasses, which can represent values outside the range of double. If you want to handle those cases correctly, it would make the method a lot more complex (you’d have to start handling different types differenty).

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