Question

I want to display all the errors stored in $error in an unordered list format. The following is the code that will display the errors.

<?php
     if (!empty($error)) {
         echo '<p class="error"><strong>Your message was NOT sent<br/> The following error(s) occurred:</strong><br/>'. '<li>' . $error . '</li>' . '</p>';
     } elseif (!empty($success)) {
         echo $success;
       }
?>

The problem is that the above code only display the first error in a list but rest of them are just showing in a separate line with no list format. All the errors are stored in the following format:

$error .= "You didn't type in your name. <br />";

I tried removing br tags but that didn’t work.

Any help would be much appreciated.
Thanks in advance 🙂

Answer 1

<?php
    if (!empty($error)) {
        $errors = explode('<br />', $error);
        echo '
<p class="error"><strong>Your message was NOT sent<br/>The following error(s) occurred:</strong></p>
<ul>
';
        foreach($errors as $error){
             echo "<li>$error</li>\n";
        }
        echo "</ul>";
    } elseif (!empty($success)) {
        echo $success;

    }
?>