Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I want to do audit logging generated SQL statements in Hibernate. I wrote Custom Interceptor that extents EmptyInterceptor. I overrided onPrepareStatement method to get generated SQL. But When I debug this code I am only getting generated SQL without parameters like this.
INSERT INTO TableA(Col1,Col2,Col3) VALUES(?,?,?) How can I get full SQL statement that contains parameter values like this from Hibernate
INSERT INTO TableA(Col1,Col2,Col3) VALUES('Value1','Value2','Value3')
In hibernate cfg, you may set hibernate.show_sql property to true, this will cause Hibernate to output the perpared statements (without the parameter values bound to a query) to stdout.
To have the precompiled statements and list of parameters bound to them logged, set log4j.logger.org.hibernate.SQL=DEBUG in your commons-logging (or underlying log system) configuration.