Question

I want to do like this:

SELECT * FROM `langCategories` ORDER BY `name` ASC WHERE ORDER BY `amount` DESC LIMIT 8,0

but this is not posible.

I have 2 sections in my site:
1. Top 8 Populars Categories

(SELECT * FROM `langCategories` ORDER BY `langCategories`.`amount` DESC LIMIT 0,8)

2. The rest of Categories order by name (excluding the top 8)
(???)

I do it with php:

$var = db_multiselect("SELECT * FROM `langCategories` ORDER BY `amount` DESC LIMIT 0,8");
$var2 = db_multiselect("SELECT * FROM `langCategories` ORDER BY `name` ASC");

$i=-1;
while ($row = mysqli_fetch_array($var)) // Save the top8 categories
{
   ++$i;
   $top8[$i] = $row["name"];
}

$i=0;
while ($row2 = mysqli_fetch_array($var2))
{
   if (!(in_array($row2["name"], $top8))) // compare the rest of categories excluding top 8
   {
      ...
   }
}

But i want to do this with a MySQL Query, how can do it?

Answer 1

Subquery!

SELECT * FROM (
  SELECT * FROM `langCategories` 
  ORDER BY `langCategories`.`amount` DESC 
  LIMIT 8,2000000000
) AS baseview 
ORDER BY name ASC

Gives you the NOT top 8 categories in alphabetical order