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Home/ Questions/Q 7001467
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:48:25+00:00 2026-05-27T20:48:25+00:00

I want to do something like this Can you transform unordered xml to match

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I want to do something like this Can you transform unordered xml to match an xsd:sequence order? bu a little more complex than that. For example:

<person> 
   <addressList>
        <address>
            <city>Chicago</city>
            <state>IL</state>
            <zip>41111</zip>
        </address>
        <address>
            <state>MO</state>
            <zip>64521</zip>
            <city>Kansas City</city>
        </address>
   </addressList>  
   <lastname>The BFG</lastname> 
   <firstname>1234567890</firstname>
</person>

I don’t have control in the schema so this sould match the schema, but when I try to deserialize throw an error… so the solution is use XSLT to transform this to match XSD format. I just want to get the same input but in different order for instance something like this:

Note that City in the 2nd address, first name, and last name was move.

<person>  
   <lastname>The BFG</lastname> 
   <firstname>1234567890</firstname>
   <addressList>
        <address>
            <city>Chicago</city>
            <state>IL</state>
            <zip>41111</zip>
        </address>
        <address>
            <city>Kansas City</city>
            <state>MO</state>
            <zip>64521</zip>
        </address>
   </addressList> 
</person>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:48:26+00:00Added an answer on May 27, 2026 at 8:48 pm

    Based on the previous link (Transform XML into specified ordering (DTD -> XSD)), the only changes we have to make are the xml inside of XSLT document and the name of the root (Top for person) and the new XSLT look like:

    <?xml version="1.0" encoding="UTF-8"?>
    <xsl:stylesheet version="1.0"
       xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
       xmlns:my="my-namespace" 
       exclude-result-prefixes="my">
      <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
        <my:person>  
           <my:lastname/> 
           <my:firstname/>
           <my:addressList>
                <my:address>
                    <my:city/>
                    <my:state/>
                    <my:zip/>
                </my:address>
           </my:addressList> 
        </my:person>
      <xsl:template match="my:*">
        <xsl:param name="source"/>
        <xsl:variable name="current-lookup-elem" select="current()"/>
        <xsl:for-each select="$source/*[name()=local-name($current-lookup-elem)]">
          <xsl:copy>
            <xsl:apply-templates select="$current-lookup-elem/*">
              <xsl:with-param name="source" select="current()"/>
            </xsl:apply-templates>
            <xsl:copy-of select="text()"/>
          </xsl:copy>
        </xsl:for-each>
      </xsl:template>
      <xsl:template match="/person">
        <xsl:apply-templates select="document('')/*/my:*">
          <xsl:with-param name="source" select="/"/>
        </xsl:apply-templates>
      </xsl:template>
    </xsl:stylesheet>
    
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