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Asked: May 11, 20262026-05-11T00:57:29+00:00 2026-05-11T00:57:29+00:00

I want to do something like this: c:\data\> python myscript.py *.csv and pass all

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I want to do something like this:

c:\data\> python myscript.py *.csv 

and pass all of the .csv files in the directory to my python script (such that sys.argv contains ['file1.csv', 'file2.csv'], etc.)

But sys.argv just receives ['*.csv'] indicating that the wildcard was not expanded, so this doesn’t work.

I feel like there is a simple way to do this, but can’t find it on Google. Any ideas?

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  1. 2026-05-11T00:57:30+00:00Added an answer on May 11, 2026 at 12:57 am

    You can use the glob module, that way you won’t depend on the behavior of a particular shell (well, you still depend on the shell not expanding the arguments, but at least you can get this to happen in Unix by escaping the wildcards 🙂 ).

    from glob import glob filelist = glob('*.csv') #You can pass the sys.argv argument 
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    Editorial Team added an answer This looks like correct usage. One thing to check --… May 11, 2026 at 6:20 pm
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    Editorial Team added an answer try $(this).next('.toggle').slideToggle(); or $(this).children('.toggle:first').slideToggle(); May 11, 2026 at 6:20 pm

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