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Home/ Questions/Q 6678637
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:15:59+00:00 2026-05-26T04:15:59+00:00

I want to do something like this: class T : IEnumerable<string>, IEnumerable<int> { string

  • 0

I want to do something like this:

class T : IEnumerable<string>, IEnumerable<int>
{
    string [] _strings = new string [20];
    int[] _ints = new int[20];

    public T() { }

    IEnumerator<string> IEnumerable<string>.GetEnumerator()
    {
        foreach (string str in _strings)
            yield return str;
    }

    IEnumerator<int> IEnumerable<int>.GetEnumerator()
    {
        foreach (int i in _ints)
            yield return i;
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        return this.GetEnumerator();
    }

}
//Using in code:
T t = new T();
foreach (int i in t)
   //to do something
foreach (string str in t)
   //to do stuff

I desire to know Is there a way to realize It or not. May be there are tricks ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:16:00+00:00Added an answer on May 26, 2026 at 4:16 am

    You’ve nearly managed to implement both interfaces – you just need to change the non-generic implementation to show which generic implementation you’re trying to delegate to. For example:

    IEnumerator IEnumerable.GetEnumerator()
    {
        return ((IEnumerable<int>)this).GetEnumerator();
    }
    

    However, because you’re implementing more than one IEnumerable<T> interface you’ll need to cast in the foreach loop to show which one to use:

    T t = new T();
    foreach (int i in (IEnumerable<int>) t)
       //to do something
    foreach (string str in (IEnumerable<string>) t)
    

    Personally I would strongly advise against doing this if possible though – it’ll cause a lot of confusion for people reading your code.

    See section 8.8.4 of the C# language specification for details of how the compiler treats the expression to iterate over in a foreach loop.

    (By using “normal” interface implementation for one of the interfaces you could provide a sort of “default” – but I don’t think that would really make it any better.)

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