Question

I want to do something like this code:

myType a;
a->foo();

void foo()
{
   cout << a->bar(); 
}
void bar()
{
   cout << a->bar2();
}
void bar2()
{
   cout << a->bar3();
}

In another word, when a member function is called, can we use the original caller?

Answer 1

You want:

cout << this->bar();

Or, more simply

cout << bar();

This IBM C++ documentation explains it pretty well. Have a look.