Question

I want to do the following in a regex:

1. allow alphanumeric characters
2. allow the # character, and comma ','
3. replace the comma ',' with a space
4. split on space


sentence = "cool, fun, house234"

>> [cool, fun, house234]

Answer 1

This is a simple way to do it:

sentence.scan(/[a-z0-9#]+/i) #=> ["cool", "fun", "house234"]

Basically it’s looking for character runs that contain a to z in upper and lower case, plus 0 to 9, and #, and returning those. Because comma and space aren’t matching they’re ignored.

You don’t show an example using # but I added it ‘cuz you said so.