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Home/ Questions/Q 8990763
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T22:34:22+00:00 2026-06-15T22:34:22+00:00

I want to do this in my Razor view: @foreach (Customer cust in Model.Customers)

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I want to do this in my Razor view:

@foreach (Customer cust in Model.Customers)
{
    <tr data-custid="@customer.GetIdAsText()">
        @Html.RenderPartial("CustomerListTableRow", cust)
    </tr>
}

As far as I understand, this should work. The foreach block contains a <tr>…</tr>. Inside that, it is in markup mode, so I need @ to switch to C# mode. The problem is that apparently the variable cust loses its type info (and value?), so it complains that it cannot cast void to object, which RenderPartial expects.

I got it working like this:

@foreach (Customer cust in Model.Customers)
{
    @:<tr data-custid="@customer.GetIdAsText()">
        Html.RenderPartial("CustomerListTableRow", cust);
    @:</tr>
}

But aside from looking puke ugly, if I let VS beautify the code, it mucks it up like this:

@foreach (Customer cust in Model.Customers)
{
    @:<tr data-custid="@customer.GetIdAsText()">
Html.RenderPartial("CustomerListTableRow", cust); @:</tr>                 }

Nice, huh? 🙂

So, why doesn’t the first solution work? How should I write it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T22:34:23+00:00Added an answer on June 15, 2026 at 10:34 pm

    Html.RenderPartial() is a void method and hence it must be enclosed it with a { } block:

    @{Html.RenderPartial("CustomerListTableRow", cust);}
    

    What you are definitely looking for is Html.Partial(), which returns an MvcHtmlString, and it can be used like this:

    @Html.Partial("CustomerListTableRow", cust)
    
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