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Home/ Questions/Q 6674213
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:43:09+00:00 2026-05-26T03:43:09+00:00

I want to evaluate a math expression which the user enters in a textbox.

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I want to evaluate a math expression which the user enters in a textbox. I have done this so far

string equation, finalString;
equation = textBox1.Text;
StringBuilder stringEvaluate = new StringBuilder(equation);
stringEvaluate.Replace("sin", "math.sin");
stringEvaluate.Replace("cos", "math.cos");
stringEvaluate.Replace("tan", "math.tan");
stringEvaluate.Replace("log", "math.log10");
stringEvaluate.Replace("e^", "math.exp");
finalString = stringEvaluate.ToString();
StringBuilder replaceI = new StringBuilder(finalString);
replaceI.Replace("x", "i");

double a;
for (int i = 0; i<5 ; i++)
 {
  a = double.Parse(finalStringI);
  if(a<0)
    break;
 }

when I run this program it gives an error "Input string was not in a correct format." and highlights a=double.Parse(finalStringI);

I used a pre defined expression a=i*math.log10(i)-1.2 and it works, but when I enter the same thing in the textbox it doesn’t.
I did some search and it came up with something to do with compiling the code at runtime.

any ideas how to do this?
i’m an absolute beginner.
thanks 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:43:09+00:00Added an answer on May 26, 2026 at 3:43 am

    The issue is within your stringEvaluate StringBuilder. When you’re replacing “sin” with “math.sin”, the content within stringEvaluate is still a string. You’ve got the right idea, but the error you’re getting is because of that fact.

    Math.sin is a method inside the Math class, thus it cannot be operated on as you are in your a = double.Parse(finalStringI); call.

    It would be a pretty big undertaking to accomplish your goal, but I would go about it this way:

    1. Create a class (perhaps call it Expression).
    2. Members of the Expression class could include Lists of operators and operands, and perhaps a double called solution.
    3. Pass this class the string at instantiation, and tear it apart using the StringBuilder class. For example, if you encounter a “sin”, add Math.sin to the operator collection (of which I’d use type object).
    4. Each operator and operand within said string should be placed within the two collections.
    5. Create a method that evaluates the elements within the operator and operand collection accordingly. This could get sticky for complex calculations with more than 2 operators, as you would have to implement a PEMDAS-esque algorithm to re-order the collections to obey the order of operations (and thus achieve correct solutions).

    Hope this helps 🙂

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