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Home/ Questions/Q 6060237
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:48:10+00:00 2026-05-23T08:48:10+00:00

I want to execute some code only when all images in a jQuery object

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I want to execute some code only when all images in a jQuery object have loaded. I can do this as follows:

var img1Load = $.Deferred();
$('#img1').load(img1Load.resolve);

var img2Load = $.Deferred();
$('#img2').load(img2Load.resolve);

$.when(img1Load, img2Load).done(function(){
    console.log('both imgs loaded');
});

This is OK, but I would like to not have to define a separate deferred object for every image. What if there are hundreds of them or if they may or may not be present on a given page? I would like to do it all at once, with something like:

$.when(allImagesHaveLoaded).done(function(){
    console.log('all imgs loaded');
});

I have tried creating an allImagesHaveLoaded function which iterates over the images, creating a new deferred object for each. The trouble is, if I return an array of these to be used as the parameter for a when, it doesn’t work (because it’s not a deferred object, it’s an array of deferred object).

I fiddled around with $.Deferred.pipe a bit as well (to try to create a chained deferred object to pass to when), but that didn’t appear to help.

Is there a sensible way of doing this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:48:11+00:00Added an answer on May 23, 2026 at 8:48 am

    There is a way to pass an array of deferred objects to $.when:

    $.when.apply($, myArray).done(...);
    
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