Question

I want to extract just the file name portion of a path. My code below works, but I’d like to know what the better (pythonic) way of doing this is.

filename = ''
    tmppath = '/dir1/dir2/dir3/file.exe'
    for i in reversed(tmppath):
        if i != '/':
            filename += str(i)
        else:
            break
    a = filename[::-1]
    print a

Answer 1

Try:

#!/usr/bin/python
import os.path
path = '/dir1/dir2/dir3/file.exe'
name = os.path.basename(path)
print name