Question

I want to format an output string with a series of variables. When I use an array of strings, this works as expected:

String[] myArray = new String[3];
// fill array with strings
System.out.printf("1: %s \n2: %s \n3: %s\n", myArray);

I want to use this to print the results of simulated dice-throws, so I use an array of ints. However, this doesn’t work:

int[] myArray = new int[3];
// fill array with numbers
System.out.printf("1: %d \n2: %d \n3: %d\n", myArray);
Exception in thread "main" java.util.IllegalFormatConversionException: d != [I

Of course, I could use myArray[0] etc. for every element, but this doesn’t seem very elegant.

Why is this so and how can I achieve the desired result?

Answer 1

printf is a variable argument method that takes a String (the format string) and an arbitrary number of arguments (to be formatted).

Varargs are implemented as arrays in Java. printf expects Object as its varargs type, therefore the internal type is Object[].

A String[] is-a Object[] (i.e. it can be cast to that type), so the elements of the String[] will be interpreted as the separate arguments.

An int[] however, can’t be cast to an Object[] so the int[] itself will be the first (and only) element of the varargs array.

Then you try to format the int[] using %d which won’t work, because an int[] is not a (single) decimal number.