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Home/ Questions/Q 619173
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:37:34+00:00 2026-05-13T18:37:34+00:00

I want to get ${1} = Title, ${2} = Open, ${3} = Bla-bla-bla. from

  • 0

I want to get ${1} = Title, ${2} = Open, ${3} = Bla-bla-bla.

from

{{Title|Open
Bla-bla-bla 
}}
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  1. Editorial Team
    Editorial Team
    2026-05-13T18:37:34+00:00Added an answer on May 13, 2026 at 6:37 pm

    What about something like this :

    $str = <<<STR
    {{Title|Open
    Bla-bla-bla 
    }}
    STR;
    
    $matches = array();
    if (preg_match("/^\{\{([^\|]+)\|([^\n]+)(.*)\}\}$/s", $str, $matches)) {
        var_dump($matches);
    }
    

    It’ll get you :

    array
      0 => string '{{Title|Open
    Bla-bla-bla 
    }}' (length=28)
      1 => string 'Title' (length=5)
      2 => string 'Open' (length=4)
      3 => string '
    Bla-bla-bla 
    ' (length=14)
    

    Which means that, after using trim on $matches[1], $matches[2], and $matches[3], you’ll get what you asked for 🙂

    Explaining the regex :

    • matching from the beginning of the string : ^
    • two { characters, that have to be escaped, as they have a special meaning
    • anything that’s not a |, at least one time : [^\|]+
      • between () so it’s captured — returned as the first part of the result
      • | has to be escaped too.
    • a | character — that has to be escaped.
    • Anything that’s not a line-break, at least one time : [^\n]+
      • between () so it’s captured too — second part of the result
    • .* virtually “anything” anynumber of times
      • between () so it’s captured too — third part of the result
    • and, finally, two } (escaped, too)
    • and an end of string : $

    And note the regex has the s (dotall) modifier ; see Pattern Modifiers, about that.

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