Question

I want to get a date in the format ‘YYYYMMdd’ (for example, today would be 20110627) format for the monday of the current week. From tomorrow through to Sunday I’d like to still print out Mondays (today’s) date. Then Next week, repeat the process

Answer 1

#monday
date -dmonday +%Y%m%d

#last monday
date -dlast-monday +%Y%m%d

#next monday
date -dnext-monday +%Y%m%d

#two mondays from now
date -d'monday+14 days' +%Y%m%d

#two mondays ago
date -d'monday-14 days' +%Y%m%d

#although, if you fancy yourself an Abraham Lincolin
date -d'monday-fortnight ago' +%Y%m%d #2 weeks ago
date -d'monday+fortnight' +%Y%m%d #2 weeks from now

#Monday Next Year
date -d'52+monday' +%Y%m%d

#However, Monday Last Year
date -d'52-monday' +%Y%m%d  #DOES NOT  WORK




#you can try a day other than monday
#and format this differently.

if a range is what your after you may need to do a few things

#Tuesday to Sunday
#since today is monday, I'll use Tuesday
echo `date -dtuesday +%Y%m%d-``date -dnext-sunday +%Y%m%d`

which would output:

20110628-20110703

More on Dates

note this only works on GNU date

I have read that:

Solaris version of date, which unable
to support -d can be resolve with
replacing sunfreeware.com version of
date