Question

I want to get a string count any letter in the string how many time it’s appeared in the string,and print the letter and the number So that what i did:

import java.util.Scanner;
public class test1 {
public static void main(String[] args) {
    String str;
    Scanner in = new Scanner(System.in);
    System.out.println("enter name");
    str = in.nextLine();
    char[] c1 = str.toCharArray();
    int[] f = new int[str.length()];
    for(int i=0;i<str.length();i++) {
        for(int j=0;j<str.length();j++) {
            if(c1[i]==c1[j]) {
                f[i]++;
            }
        }
    }
    for(int k=0;k<c1.length;k++) {
        for(int l=0;l<c1.length;l++) {
            if(c1[k]==c1[l]) {
                if(l!=k) {c1[k]=0;f[k]=0;}
            }
        }
        System.out.println(c1[k]+"="+f[k]);
    }
}
}

There are two problems:
1. when i print it’s printing the duplicated letter twice(or thrice or more depends how many times the letter is in the string).
so i added the another 2 loops(k and l) that deletes the duplicated letters,but now instead of the duplicated letter it’s print me: an square and a zero,how i can just get delete the letter and the number from the char and int array’s?(for example when i insters the name “elichai” i get:

e=1
l=1
(an square)=0
c=1
h=1
a=1
i=2

2.The letter it deletes is the second letter not the first
(in “elichai” example it’s deleted the first ‘i’ instead of the second ‘i’)
Thanks!

Answer 1

Different approach to solve your problem, but this is how I would probably do it:

String input = "Whatever";
Map<Character, Integer> charCounter = new LinkedHashMap<>(); // respects insertion order
for (char c : input.replaceAll("\\s+", "").toCharArray()) { // ignore spaces
    Integer count = charCounter.get(c);
    count = count == null ? 0 : count;
    charCounter.put(c, count + 1);
}
System.out.println(charCounter);