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Home/ Questions/Q 8233081
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T18:00:59+00:00 2026-06-07T18:00:59+00:00

I want to get all the iframe from a webpage. Code: site = http://

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I want to get all the iframe from a webpage.

Code:

site = "http://" + url
f = urllib2.urlopen(site)
web_content =  f.read()

soup = BeautifulSoup(web_content)
info = {}
content = []
for iframe in soup.find_all('iframe'):
    info['src'] = iframe.get('src')
    info['height'] = iframe.get('height')
    info['width'] = iframe.get('width')
    content.append(info)
    print(info)       

pprint(content)

result of print(info):

{'src': u'abc.com', 'width': u'0', 'height': u'0'}
{'src': u'xyz.com', 'width': u'0', 'height': u'0'}
{'src': u'http://www.detik.com', 'width': u'1000', 'height': u'600'}

result of pprint(content):

[{'height': u'600', 'src': u'http://www.detik.com', 'width': u'1000'},
{'height': u'600', 'src': u'http://www.detik.com', 'width': u'1000'},
{'height': u'600', 'src': u'http://www.detik.com', 'width': u'1000'}]

Why is the value of the content not right? It’s suppose to be the same as the value when I print(info).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T18:01:01+00:00Added an answer on June 7, 2026 at 6:01 pm

    You are not creating a separate dictionary for each iframe, you just keep modifying the same dictionary over and over, and you keep adding additional references to that dictionary in your list.

    Remember, when you do something like content.append(info), you aren’t making a copy of the data, you are simply appending a reference to the data.

    You need to create a new dictionary for each iframe.

    for iframe in soup.find_all('iframe'):
        info = {}
        ...
    

    Even better, you don’t need to create an empty dictionary first. Just create it all at once:

    for iframe in soup.find_all('iframe'):
        info = {
            "src": iframe.get('src'),
            "height": iframe.get('height'),
            "width": iframe.get('width'),
        }
        content.append(info)
    

    There are other ways to accomplish this, such as iterating over a list of attributes, or using list or dictionary comprehensions, but it’s hard to improve upon the clarity of the above code.

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