Question

I want to get the source code of a web page that the users enters. When he presses the button, he should see the source in a TextView. This is my code:

final Button b = (Button) findViewById(R.id.button1);

        b.setOnClickListener(new OnClickListener() {

            public void onClick(View v) {
                // TODO Auto-generated method stub

                try {
                    URL url = null;
                    url = new URL(myEditText.getText().toString());
                    URLConnection conn = url.openConnection();
                    BufferedReader reader = new BufferedReader(
                            new InputStreamReader(conn.getInputStream()));
                    String line = "";
                    while ((line = reader.readLine()) != null) {
                        myTextView.append(line);

                    }

                } catch (Exception e) {

                    Log.e("ERR",e.getMessage());
                }

            }
        });

When I run it I get a NullPointerException at

BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream())); 

.–>Println needs a message.

I don’t know what is wrong, since this is from a video tutorial. I have written <uses-permission android:name="android.permission.INTERNET"/> in Manifest so, everything should be allright.

Answer 1

try this.

url = new URL("http://www.stackoverflow.com");

if it works then you need to set validation for like isValidUrl() ?

Because user may have entered wrong URL.