Question

I want to have one callback function after actions are done, I’m trying something like this:

$.when(
    $('#detail1').load('/getInfo.php'),
    $('#detail2').load('/getOther.php')
        ).then(function(a,b){
            alert("done");
        }); 

The problem is that the callback function is firing before the actions are finished.

Answer 1

This is because jQuery.when() expects jQuery.Deferred instances while load() returns an jQuery instance (see http://api.jquery.com/jQuery.when/ and http://api.jquery.com/load/).

You can work around this issue:

// Create two Deferred instances that can be handed to $.when()
var d1 = new $.Deferred();
var d2 = new $.Deferred();

// Set up the chain of events...
$.when(d1, d2).then(function() {
    alert('done');
});

// And finally: Make the actual ajax calls:
$('#detail1').load('/getInfo.php', function() { d1.resolve(); });
$('#detail2').load('/getOther.php', function() { d2.resolve(); });