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Home/ Questions/Q 7733953
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T07:07:42+00:00 2026-06-01T07:07:42+00:00

I want to implement a multithread system (two threads will do) and I followed

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I want to implement a multithread system (two threads will do) and I followed a tutorial

    Thread t1 = new Thread(new ThreadStart(threadA));
    Thread t2 = new Thread(new ThreadStart(threadB));
    t1.Start();
    t2.Start();

The output is unexpected for me as it shows:
“threadA”
“threadA”
“threadA”
“threadB”
“threadB”
“threadB”.
Is something wrong with my code? Many thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T07:07:44+00:00Added an answer on June 1, 2026 at 7:07 am

    This is happening because in the time that it takes for you to go from t1.Start() to t2.Start(), your t1 has already completed.

    Try something like this if you want to see your code alternate a little

    Thread t1 = new Thread(
        new ThreadStart(()=>
        {
            for(int i = 0; i < 3; i++)
            {
                System.Console.WriteLine("ThreadA");    
                Thread.Sleep(3000)
            }
        }));
    Thread t2 = new Thread(
        new ThreadStart(()=>
        {
            for(int i = 0; i < 3; i++)
            {
                System.Console.WriteLine("ThreadB");    
                Thread.Sleep(1000)
            }
        }));
    t1.Start();
    t2.Start();
    

    It should print something like this:

    ThreadA
    ThreadB
    ThreadB
    ThreadA
    ThreadB
    ThreadA
    

    However, this just shows that you cannot guarantee any order when it comes to threading.

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