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Home/ Questions/Q 7698497
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T22:15:23+00:00 2026-05-31T22:15:23+00:00

I want to implement my own copy method for a class A which looks

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I want to implement my own copy method for a class A which looks like this:

class A(object):
    def __init__(self):
        self.field1 = generate_a_list_of_ints()
    def __copy__(self):
        result = A()
        result.fiel1[:] = self.field1[:]
        return result

The problem with the code above is that when copying an A object, the initialization code will be invoked even though there is no need to get the initial values.

How can I copy the field1 without running initialization code? I looked for information about __new__ but most of it was referring to factories and stuff that seemed unrelated, so it’s still unclear to me how to skip the initialization.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T22:15:24+00:00Added an answer on May 31, 2026 at 10:15 pm

    I suggest an optional argument in your __init__() method, like so:

    class A(object):
        def __init__(self, init=True):
            if init:
                self.field1 = generate_a_list_of_ints()
        def __copy__(self):
            result = A(init=False)
            result.fiel1[:] = self.field1[:]
            return result
    
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