Home/ Questions/Q 4255606
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-21T05:14:30+00:00

I want to incorporate a session variable $_SESSION[‘LI’] into the jQuery with an if

  • 0

I want to incorporate a session variable $_SESSION['LI'] into the jQuery with an if statement.
So if($_SESSION['LI'] == 'falsus') hide the #feedback else show #feedback.

Thanks

<?php
session_start();
$_SESSION['LI'] = 'falsus';
?><html>
    <head>
        <title></title>
        <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
        <script type="text/javascript">
        $(document).ready(function() {
            $('#feedback').hide();
        });
        </script>
    </head>
    <body>
        <div id="feedback">Hello</div>
        <? print_r($_SESSION);?>
    </body>
</html>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Could you just do something like this:

    <?php
    session_start();
    $_SESSION['LI'] = 'falsus';
?>
<html>
    <head>
        <title></title>
        <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
        <?php if($_SESSION['LI'] == 'falsus'): ?>
            <script type="text/javascript">
                $(document).ready(function() {
                    $('#feedback').hide();
                });
            </script>
        <?php endif; ?>
    </head>
    <body>
        <div id="feedback">Hello</div>
        <? print_r($_SESSION);?>
    </body>
</html>

    This will only add the script to hide the #feedback div when the session variable is "falsus". If it is NOT "falsus", then the whole script block is omitted.

    • 0