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Home/ Questions/Q 8447635
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T10:13:42+00:00 2026-06-10T10:13:42+00:00

I want to integrate exp(-(x^2 + y^2)) in python using sympy library. I could

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I want to integrate exp(-(x^2 + y^2)) in python using sympy library.
I could find the integral of exp(-(x^2))

>>> B1 = sympy.exp(-alpha1 * (r1_x**2))
>>> p = integrate(B1,r1_x)
>>> p
pi**(1/2)*erf(alpha1**(1/2)*r1_x)/(2*alpha1**(1/2))

But when I want to try integrate exp(-(x^2 + y^2))

>>> B1 = sympy.exp(-alpha1 * (r1_x**2 + r1_y**2))
>>> p = integrate(B1,r1_x)
>>> p
Integral(exp(-alpha1*(r1_x**2 + r1_y**2)), r1_x)

There is no output and python can’t take the integral!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T10:13:43+00:00Added an answer on June 10, 2026 at 10:13 am

    sympy doesn’t always recognize every form, and so sometimes you have to give it a little help:

    >>> import sympy
    >>> alpha1, r1_x, r1_y = sympy.var("alpha1 r1_x r1_y")
    >>> B1 = sympy.exp(-alpha1 * (r1_x**2 + r1_y**2))
    >>> B1.integrate(r1_x)
    Integral(exp(-alpha1*(r1_x**2 + r1_y**2)), r1_x)
    >>> B1.expand(alpha1)
    exp(-alpha1*r1_x**2)*exp(-alpha1*r1_y**2)
    >>> B1.expand(alpha1).integrate(r1_x)
    sqrt(pi)*exp(-alpha1*r1_y**2)*erf(sqrt(alpha1)*r1_x)/(2*sqrt(alpha1))
    
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