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Home/ Questions/Q 6964755
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T15:57:52+00:00 2026-05-27T15:57:52+00:00

I want to iterate over records in the database and update them. However since

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I want to iterate over records in the database and update them. However since that updating is both taking some time and prone to errors, I need to a) don’t keep the db waiting (as e.g. with a ScrollableResults) and b) commit after each update.
Second thing is that this is done in multiple threads, so I need to ensure that if thread A is taking care of a record, thread B is getting another one.
How can I implement this sensibly with hibernate?

To give a better idea, the following code would be executed by several threads, where all threads share a single instance of the RecordIterator:

Iterator<Record> iter = db.getRecordIterator();
while(iter.hasNext()){
    Record rec = iter.next();
    // do something lengthy here
    db.save(rec);
}

So my question is how to implement the RecordIterator. If on every next() I perform a query, how to ensure that I don’t return the same record twice? If I don’t, which query to use to return detached objects? Is there a flaw in the general approach (e.g. use one RecordIterator per thread and let the db somehow handle synchronization)? Additional info: there are way to many records to locally keep them (e.g. in a set of treated records).

Update: Because the overall process takes some time, it can happen that the status of Records changes. Due to that the ordering of the result of a query can change. I guess to solve this problem I have to mark records in the database once I return them for processing…

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  1. Editorial Team
    Editorial Team
    2026-05-27T15:57:52+00:00Added an answer on May 27, 2026 at 3:57 pm

    Hmmm, what about pushing your objects from a reader thread in some bounded blocking queue, and let your updater threads read from that queue.

    In your reader, do some paging with setFirstResult/setMaxResults. E.g. if you have 1000 elements maximum in your queue, fill them up 500 at a time. When the queue is full, the next push will automatically wait until the updaters take the next elements.

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