Question

I want to iterate over the argument list in shell, I know how to do this with

for var in $@

But I want to do this with

for ((i=3; i<=$#; i++))

I need this because the first two arguments won’t enter into the loop. Anyone knows how to do this? Looking forward to you help.

cheng

Answer 1

This might help:

for var in "${@:3}"

for more information you can look at:

http://www.ibm.com/developerworks/library/l-bash-parameters/index.html