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Home/ Questions/Q 7957571
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:16:13+00:00 2026-06-04T04:16:13+00:00

I want to make a function pointer array and be able to call them

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I want to make a function pointer array and be able to call them in a for-loop. How can I achieve this? I have tried:

void (**a) (int);
a[0] = &my_func1;
a[1] = &my_func2;
a[2] = &my_func3;

for ( i = 0; i < 3; i++){
    a[0]();
    (*a[0])(); // Neither does work
}

But I am missing some syntax I guess:

error: too few arguments to function ‘*(a + (long unsigned int)((long unsigned int)i * 8ul))’
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  1. Editorial Team
    Editorial Team
    2026-06-04T04:16:14+00:00Added an answer on June 4, 2026 at 4:16 am

    I guess the below code is what you need.

    typedef void * func_pointer(int);
    
    func_pointer fparr[10];
    
    for(int i = 0; i<10; i++)
    {
         fparr[i](arg); //pass the integer argument here
    }
    
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