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Home/ Questions/Q 7167179
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:32:08+00:00 2026-05-28T14:32:08+00:00

I want to make a multi-threaded downloader (in Python) and I need to tell

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I want to make a multi-threaded downloader (in Python) and I need to tell each thread where to start and how many bytes to download. For that I get the remote file size and divide it, for example, to 2. Now, let’s say that the remote file size is 5: when I divide the number to 2, I get 2 as result. Now I can start the download but I will lose a byte (because 2*2=4, not 5). I can’t use float numbers because I can’t download half of a byte. How I could divide that number and to get a list with [2, 3], for example?

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  1. Editorial Team
    Editorial Team
    2026-05-28T14:32:09+00:00Added an answer on May 28, 2026 at 2:32 pm

    Use divmod:

    >>> divmod(5, 2)
    (2, 1)
    >>>
    

    This tells you, that 5 divided by 2 is 2, remainder 1, so the last piece will be 2 + 1 = 3.

    >>> divmod(12345, 6)
    (2057, 3)
    

    Here, you’ll have 5 chunks at 2057 and a last slice at 2057+3.

    This algorithm will also work for cases, where division is without remainder:

    >>> divmod(12345, 5)
    (2469, 0)
    

    Here, you’ll have 4 chunks at 2469 plus a last slice at 2469+0.

    So, your chunk sizes could be computed as:

    def chunk_sizes(filesize, num_chunks):
        d, r = divmod(filesize, num_chunks)
        result = [d] * num_chunks
        result[-1] += r
        return result
    
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