Question

I want to make a Python code that will open a program like cmd would, then export a .txt file from the file menu. The code looks like this for cmd:

c:\ESG\Statsvis.exe \\192.168.100.222\c\ESG\S1-424\2012\06\29\S1-42420120629.dsf /output=C:\Users\jessica.macleod\Desktop\outfile.txt /param=RMS Amplitude

In cmd, the above line does exactly what I want. What would be the equivalent for Python?

Answer 1

See subprocess.Popen, like this:

subprocess.Popen(["/bin/ls", "-l"]

Or, depending on what you want to get as result (stdout, return code), use subprocess.call, subprocess.call_check, or other snippets in this module.