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Home/ Questions/Q 4615834
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T01:53:47+00:00 2026-05-22T01:53:47+00:00

I want to make a simple action in which when i press a button

  • 0

I want to make a simple action in which when i press a button then i should jump to another activity. But in this program whenever i press submit button an error is occurred and program terminated.

Please check my code and help me what error i have done.

My first activity

package login.test;

import android.app.Activity;
import android.os.Bundle;
import android.content.*;
import android.widget.*;
import android.view.View;

import android.view.View.OnClickListener;

public class login extends Activity  
{
    /** Called when the activity is first created. */
    EditText e;
    Button b;
    @Override

    public void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
         b=(Button)findViewById(R.id.submit);
       e=(EditText)findViewById(R.id.editText1);

    b.setOnClickListener( new OnClickListener()
    {

       @Override
       public void onClick(View v)
        {
           if (v.getId() == R.id.submit) 
            {
               Intent myIntent = new Intent(v.getContext(), some.class);
               startActivityForResult(myIntent, 0);

            } 
            else
            {
                e.setText("cant go");
            }
       }
    });
    }
}

second Activity

package login.test;
import android.os.Bundle;
import android.app.Activity;
import android.content.*;
import android.widget.*;
import android.view.View;
import android.view.View.OnClickListener;

public class some extends Activity {
     public void onCreate(Bundle savedInstanceState) 
        {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.welcome);
        }
}

main.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent" android:orientation="vertical">
<TextView  
    android:layout_width="fill_parent" 
    android:layout_height="wrap_content" 
    android:text="saan"
    />

<Button android:text="Submit" android:id="@+id/submit" android:layout_width="wrap_content" android:layout_height="wrap_content"></Button>
<EditText android:layout_width="match_parent" android:layout_height="wrap_content" android:text="EditText" android:id="@+id/editText1"></EditText>
</LinearLayout>

welcome.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
  xmlns:android="http://schemas.android.com/apk/res/android"
  android:layout_width="match_parent"
  android:layout_height="match_parent">
    <EditText android:text="You are welcome" android:id="@+id/editText1" android:layout_width="wrap_content" android:layout_height="wrap_content"></EditText>
</LinearLayout>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T01:53:48+00:00Added an answer on May 22, 2026 at 1:53 am

    I think you missed add your second activity in menifest..

    So plz add second activity in menifest.

    and second thing is no need to check

    if (v.getId() == R.id.submit) 
    

    because you setOnClickListener on button so v will always button.

    remove this condition

    compare my code with your..

    b.setOnClickListener( new OnClickListener()
        {
    
           @Override
           public void onClick(View v)
            {
               Intent myIntent = new Intent(login.this, some.class);
               startActivityForResult(myIntent, 0);
    
    
           }
        });
    
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