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Home/ Questions/Q 9125645
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T06:51:07+00:00 2026-06-17T06:51:07+00:00

i want to make a simple command line java app that gets as argument

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i want to make a simple command line java app that gets as argument the name of a file located in the same directory with the jar file of the app, so that i can read from it. however i’m getting a FileNotFoundException. here’s my code:

public static void main(String[] args) {
    if (args.length == 0) {
        System.out.println("Give the name of the input file as argument.");
    } else if (args.length > 1) {
        System.out.println("Only one input file is allowed");
    } else {
        try {
            BufferedReader in = new BufferedReader(new FileReader(args[0]));
            System.out.println("File found");
        } catch (FileNotFoundException e) {
            System.out.println("Could not find file " + args[0]);
        }
    }
}

so suppose i’m having a txt file named a.txt and myApp.jar file inside the same directory.
i start cmd and cd to this specific directory, and then type:

java -jar myApp.jar a.txt

and i get “Could not find file a.txt”

what am i doing wrong?

EDIT: after thinking of it i guess the file is not found because it should be in the same directory with the class file, in other words inside the jar. so my question is, how is it possible to access it when it is outside of the jar file?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T06:51:08+00:00Added an answer on June 17, 2026 at 6:51 am

    The “current” directory is going to be determined by the environment when you launch your application. To find out where it’s looking, change the error output line to be:

    System.out.println("Could not find file " + (new File(args[0])).getCanonicalPath());
    

    (you may have to add throws IOException to your main() declaration to get the above to compile).

    If you want to access resources inside the classpath (or jar), use ClassLoader.getResourceAsStream – you will then wrap a Reader around the returned InputStream using InputStreamReader.

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