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Home/ Questions/Q 8720851
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:07:27+00:00 2026-06-13T07:07:27+00:00

I want to make a wrapper class that behaves in exactly the same way

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I want to make a wrapper class that behaves in exactly the same way as the wrapped object (with a few specific exceptions). The problem I’m having at the moment is with built-in functions. How could I redirect built-in functions to the wrapped object?

class Wrapper:
    def __init__(self, wrapped):
        object.__setattr__(self, '_wrapped', wrapped)
    def __getattr__(self, name):
        return getattr(object.__getattribute__(self, '_wrapped'), name)

class Foo:
    def __init__(self, val):
        self.val = val
    def __abs__(self):
        return abs(self.val)

foo = Wrapper(Foo(-1))
print(foo.val) # Okay
print(abs(foo)) # TypeError: bad operand type for abs(): 'Wrapper'
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:07:28+00:00Added an answer on June 13, 2026 at 7:07 am

    You can dynamically create a new class that is subclass of both Wrapper and Foo, so you’ll have all the properties needed:

    class Wrapper:
        def __new__(self, wrapped):
            cls = type(wrapped)
            new_type = type(cls.__name__ + '_wrapped', (Wrapper, cls), {})
            return object.__new__(new_type)
    
        def __init__(self, wrapped):
            self._wrapped = wrapped
        def __getattr__(self, name):
            return getattr(self._wrapped, name)
    

    So now you can do:

    >>> foo = Wrapper(Foo(-1))
    >>> abs(foo)
    1
    >>> type(foo)
    <class '__main__.Foo_wrapped'>
    

    PS:

    • You don’t need object.__getattr__ (or __setattr__) in the __init__ and __getattr__ functions to get and set this attribute.
    • You may want to cache this operation to avoid creating a new class at every new object.
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